gvSIG bugs #3609
The "?" doesn't work when using the "like" parameter at the Filter tool
| Status: | Invalid | % Done: | 0% | |
|---|---|---|---|---|
| Priority: | Normal | Spent time: | - | |
| Assignee: | - | |||
| Category: | - | |||
| Target version: | 2.3.0-2400 (rev. org.gvsig.desktop-2.0.102) | |||
| Severity: | Minor | Add-on version: | ||
| gvSIG version: | 2.2.0 | Add-on build: | ||
| gvSIG build: | 2313 | Add-on resolve version: | ||
| Operative System: | Add-on resolve build: | |||
| Keywords: | Proyecto: | |||
| Has patch: | Hito: | |||
| Add-on name: | Unknown |
Description
The "?" indicates a character when using the "like" parameter at the Filter tool. It doesn't work in gvSIG 2.2.
Example:
FIELD like '??xt'
(it would find the word "text" for example)
Related issues
History
#1
Updated by Mario Carrera almost 11 years ago
- Related to gvSIG bugs #3608: There's an error in the Filter tool when the text has an apostrophe added
#2
Updated by Antonio Falciano almost 11 years ago
- Status changed from New to Invalid
Hi Mario,
use the underscore as wildcard char for a single character (see #3608).
http://www.w3schools.com/sql/sql_wildcards.asp
#3
Updated by Joaquín del Cerro Murciano almost 11 years ago
- Target version set to 2.3.0-2400 (rev. org.gvsig.desktop-2.0.102)